clear all;
clc;

Non-Iterative Solver

tic;
j = 1;
for M = 0:0.01:pi
    i = 1;
    for e = 0:0.01:1
        a   =  (1 - e)*3/(4*e+0.5);
        b   =  -M/(4*e+0.5);
        y   =  (b^2/4 + a^3/27)^0.5;
        x   =  (-b/2 + y)^(1/3) - (b/2 + y)^(1/3);
        w   =  x - 0.078*x^5/(1 + e);
        E   =  M + e*(3*w - 4*w^3);
        % Two times applying 5th-order Newton correction
        for k = 1:2
            f   =  (E - e*sin(E)- M);
            fd  =  1 - e*cos(E);
            f2d =  e*sin(E);
            f3d = -e*cos(E);
            f4d =  e*sin(E);
            E = E -f/fd*(1 + f*f2d/(2*fd^2) + f^2*(3*f2d^2 - fd*f3d)/(6*fd^4)+...
                (10*fd*f2d*f3d - 15*f2d^3-fd^2*f4d)*f^3/(24*fd^6));
        end
        E_nit(i,j) = E;
        i = i + 1;
    end
    j = j + 1;
end
t_nit = toc;
fprintf('Calculation time = %4.6f [s] \n',t_nit);
Calculation time = 0.149860 [s]

Newton Iterative Solver

tic;
j = 1;
eps = 1E-15;        % Tolerance
for M = 0:0.01:pi
    i = 1;
    for e = 0:0.01:1
        En  = M;
        Ens = En - (En-e*sin(En)- M)/(1 - e*cos(En));
        while ( abs(Ens-En) > eps )
            En = Ens;
            Ens = En - (En - e*sin(En) - M)/(1 - e*cos(En));
        end;
        E_it(i,j) = Ens;
        i = i + 1;
    end
    j = j + 1;
end
t_it = toc;
fprintf('Calculation time = %4.6f [s] \n',t_it);

Calculation time = 0.893673 [s]

Error = log10(abs(E_it - E_nit));
e = 0:0.01:1;
M = (0:0.01:pi);
contourf (M,e,Error);
xlabel('M - Mean anomaly [rad]');
ylabel('e - Eccentricity');
title('Non-Iterative Solver,Error in E calculation on Log scale [rad] ');
colorbar;


[6] S. Mikkola, “A Cubic Approximation for Kepler’s Equation,” Celestial
 Mechanics and Dynamical Astronomy,Vol. 40, 1987, pp. 329–334.